Description:-
Today I am going to explain how to capture infolog
messages for a particular record and show those logs on click of a log button
on a form.
1) Create a job which inserts records into a table, prints some info messages and capture them.
logTable contains three fields name and infolog. info is a field created with EDT infologData and visible property is set to NO. info is a container which stores the infolog messages for the particular record.
Example:-
1) Create a job which inserts records into a table, prints some info messages and capture them.
logTable contains three fields name and infolog. info is a field created with EDT infologData and visible property is set to NO. info is a container which stores the infolog messages for the particular record.
Example:-
static void TestJob(Args _args) { InfoLogStatusTable insertLog; InfologData msg; ttsbegin; insertLog.initValue(); insertLog.Name= "Umesh"; //info(strFmt("%1", insertLog.Infolog)); //info(strFmt("Entered Name :- %1", insertLog.Name)); info(strFmt("name %1 created successfully", insertLog.Name)); msg = infolog.infologData(); insertLog.Infolog = msg; insertLog.insert(); infolog.import(msg); ttscommit; }
NOTE :-
i) Save compile and run this job. name is hard coded. These two values are inserted into table.
ii) The info stored for this record are :
name Umesh created successfully
2) Now create a form with grid showing the logTable datasource fields and button named log.
Write the following code in clicked method of the button
void clicked() { InfologData msg; msg = InfoLogStatusTable.Infolog; infolog.import(msg); }
Now when you select this particular record and press the log button the infolog
messages stored for this record are displayed in info.
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